![\huge\underline\mathcal{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}](https://img.qammunity.org/2023/formulas/mathematics/college/pimbwwc3phzb8a585x924ckhk1fkfrg42g.png)
the question asks us to find the values of y.
the question can be solved as follows ~
![\longrightarrow \: 5y {}^(2) - 17y = - 6](https://img.qammunity.org/2023/formulas/mathematics/college/tp3vufw62bz3sy77jf3rc9pxzd9ehghpxi.png)
let's first convert the equation into its general formula , i.e. , ax² + bx + c = 0
![\longrightarrow \: 5y {}^(2) - 17y + 6 = 0](https://img.qammunity.org/2023/formulas/mathematics/college/h17z6m6w41gk8siqt7rioogj63tln23dnv.png)
using splitting the middle term , let's find out the factors of the given equation ~
![\longrightarrow \: 5y {}^(2) - 15y - 2y + 6 = 0 \\ \\ \longrightarrow \: 5y \: (y - 3) - 2 \: (y - 3) = 0 \\ \\ \longrightarrow \: 5y - 2 = 0 \: \: \: or \: \: \: y - 3 = 0 \\ \\ \longrightarrow \:\boxed{ y = (2)/(5)} \: \: \: or \: \: \: \boxed{y = 3}](https://img.qammunity.org/2023/formulas/mathematics/college/cqv3gle84kdo5mgmhscbkdb8v0v3hlmib6.png)
hope helpful ~