Answer:
![- 2x^5+ 0x^4 + (x^3)/(2) +0x^2+(x)/(4) + 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/mab32040fi9rzs7ixhiiy46cpbevnak9qf.png)
Explanation:
Given
![(x)/(4) - 2x^5 + (x^3)/(2) + 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/cbgs7jhz82f3ks463nx7iy0kb80f7vvptw.png)
Required
The standard form of the polynomial
The general form of a polynomial is
![ax^n + bx^(n-1) + cx^(n-2) +........+ k](https://img.qammunity.org/2021/formulas/mathematics/high-school/w71qjioavnnfxz75fphdtq2n2z6x7r1k1o.png)
Where k is a constant and the terms are arranged from biggest to smallest exponents
We start by rearranging the given polynomial
![- 2x^5+ (x^3)/(2) +(x)/(4) + 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/l0ucrgpogz2n4wzth4usg45tnqdusxpqc0.png)
Given that the highest exponent of x is 5;
Let n = 5
Then we fix in the missing terms in terms of n
![- 2x^5+ 0x^(n-1) + (x^3)/(2) +0x^(n-3)+(x)/(4) + 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ppnr89u7tcqslu0b5tjrjjqtxnkii7ugrx.png)
Substitute 5 for n
![- 2x^5+ 0x^(5-1) + (x^3)/(2) +0x^(5-3)+(x)/(4) + 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/myp1huctkhqgxvktd0bk0t2ddrcy69r0z3.png)
![- 2x^5+ 0x^(4) + (x^3)/(2) +0x^(2)+(x)/(4) + 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/dlyye0nmbjv6au2md2wkjsrymfllp17kf9.png)
Hence, the standard form of the given polynomial is
![- 2x^5+ 0x^4 + (x^3)/(2) +0x^2+(x)/(4) + 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/mab32040fi9rzs7ixhiiy46cpbevnak9qf.png)