Question

Find the volume of the cone

Answer 1

12
`\pi` units^3

Explanation:

V=1/3Bh

=1/3 Area of the base times height

Area of base:
`\pi`r^2=4
`\pi`

height=9

4
`\pi` times 9=36
`\pi`

1/3 of 36
`\pi` =12
`\pi`

Answer 2

The volume of cone is
`\boxed{\tt{37.68}}` units³.

Step-by-step explanation:

As per given question we have provided :

• ➝ Radius of cone = 2 units
• ➝ Height of cone = 9 units

Here's the required formula to find the volume of cone :

`{\longrightarrow{\pmb{\sf{V_((Cone)) = (1)/(3)\pi{r}^(2)h}}}}`

• ➝ V = Volume
• ➝ π = 3.14
• ➝ r = radius
• ➝ h = height

Substituting all the given values in the formula to find the volume of cone :

`{\implies{\sf{Volume_((Cone)) = (1)/(3)\pi{r}^(2)h}}}`

`{\implies{\sf{Volume_((Cone)) = (1)/(3) * 3.14{(2)}^(2)9}}}`

`{\implies{\sf{Volume_((Cone)) = (1)/(3) * 3.14{(2 * 2)}9}}}`

`{\implies{\sf{Volume_((Cone)) = (1)/(3) * 3.14{(4)}9}}}`

`{\implies{\sf{Volume_((Cone)) = (1)/(3) * 3.14 * 4 * 9}}}`

`{\implies{\sf{Volume_((Cone)) = (1)/(3) * 3.14 * 36}}}`

`{\implies{\sf{Volume_((Cone)) = \frac{1}{\cancel{3}}* 3.14 * \cancel{36}}}}`

`{\implies{\sf{Volume_((Cone)) = 3.14 * 12}}}`

`{\implies{\sf{Volume_((Cone)) = 37.68}}}`

`\star{\underline{\boxed{\sf{\red{Volume_((Cone)) = 37.68 \: {units}^(3)}}}}}`

Hence, the volume of cone is 37.68 units³.

`\rule{300}{2.5}`