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A submarine hovers at 66 and two-thirds yards below sea level. If it ascends 24 and StartFraction 1 over 8 EndFraction yards and then descends 78 and three-fourths yards, what is the submarine’s new position, in yards, with respect to sea level? Negative 169 and StartFraction 13 over 24 EndFraction Negative 121 and StartFraction 7 over 24 EndFraction Negative 12 and StartFraction 1 over 24 EndFraction 12 and StartFraction 1 over 24 EndFraction

2 Answers

7 votes

Answer:

The answer-121 and 7/24

Hope this helps

:D

If I'm wrong sorry

And sorry that I'm super late

User NJENGAH
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A submarine hovers at 66 and 2/3 yards below sea level. If it ascends 24 and 1/8 yards and then descends again 78 and 3/4 yards, what is the submarine’s new position, in yards, below sea level?

Answer:

The submarine's new position is
-121(7)/(24)\text{ yards} below sea level.

Solution:

Given that a submarine hovers at
66(2)/(3) yards below sea level. This means that the position of submarine is negative

Therefore, we get
-66(2)/(3)

Also given that it ascend
24(1)/(8) yards

So we have to add
-66(2)/(3) and
24(1)/(8)


\rightarrow -66(2)/(3) + 24(1)/(8)\\\\\text{Convert mixed fractions to improper fractions }\\\\\rightarrow -(66 * 3+2)/(3) + (24 * 8+1)/(8) = (-200)/(3) + (193)/(8)\\\\\rightarrow (-200 * 8)/(3 * 8) + (193 * 3)/(8 * 3)\\\\\text{Simplify the above expression }\\\\\rightarrow (-1600)/(24) + (579)/(24) = (-1021)/(24)

The submarine descends again 78 and 3/4 yards

This means we need to subtract
-78(3)/(4)\text{ yards from } -(1021)/(24)\text{ yards}


\rightarrow (-1021)/(24) -(78(3)/(4))\\\\\rightarrow (-1021)/(24) - (78 * 4 + 3)/(4)\\\\\rightarrow (-1021)/(24) - (315)/(4) = (-1021)/(24) - (315 * 6)/(4 * 6)\\\\\rightarrow (-1021 -1890)/(24) = (-2911)/(24)\\\\\text{Simplify the expression }\\\\\rightarrow (-2911)/(24) = -121(7)/(24)

Therefore, the submarine's new position is
-121(7)/(24)\text{ yards} below sea level.

User CCSab
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