Answer:
Q2 = (B). 2
Q2 = (B). 2Q7 = (C) 9x - 2y = -40
Explanation:
Hello?
Q2:
When solving this problem, first you have to write
down the equation of the line (linear function).
Here, I choose to use Point Intercept Form
Take the first 2 points.
.(-1 , -12) & (2, 0)
The gradient = ∆y/∆x
= (0 - -12)/ (2 - - 1), (12/3)
= 4
The Equation:
(y - 0) = 4(x - 2)
y = 4x - 8
y = 4x - 8Zero of the function; f(x) = mx + c
0 = 4x - 8
8 = 4x
x = 2
Q7
Values given:
Gradient: 9/2, Points (-4, 2)
Using the Point Intercept form of Equation,
(y - 2) = 9/2(x - -4)
Opening the brackets
y - 2 = 9/2x + 18
Simplifying
y = 9/2x + 20
Multiply through by 2 gives
2y = 9x + 40
Taking x to the LHS
-9x + 2y = 40
Divide through by -1
Gives
9x - 2y = - 40 <<<<<<< what we are looking for
I hope this helps. Have a nice studies.