What are the zeros of the quadratic function f(x) = 6x2 + 12x-7?

Question

asked May 1, 2022 19.8k views

2 Answers

Astro · Answer 1 · 2022-05-06T16:57:51+0000

Given:

The quadratic function is:

f(x)=6x^2+12x-7

To find:

The zeros of the quadratic function.

Solution:

Quadratic formula: If a quadratic equation is
ax^2+bx+c=0 , then zeros of the quadratic equation are:

$x=(-b\pm √(b^2-4ac))/(2a)$

We have,

f(x)=6x^2+12x-7

For zeros,
f(x)=0 .

6x^2+12x-7=0

Here,
a=6,b=12,c=-7 . Using quadratic formula, we get

$x=(-12\pm √((12)^2-4(6)(-7)))/(2(6))$

$x=(-12\pm √(144+168))/(12)$

$x=(-12\pm √(312))/(12)$

$x=(-12\pm 17.6635)/(12)$

Now,

x=(-12+17.6635)/(12) and
x=(-12-17.6635)/(12)

x=0.47195833... and
x=-2.47195833...

$x\approx 0.472$ and
$x\approx -2.472$

Therefore, the zeros of the given quadratic function are 0.472 and -2.472.