Question

In order to make 0.500 L of a 0.475 M solution, you will need to weigh out how many grams of sucrose (MM = 342 g/mol)?

Answer 1

To make a 0.500 L of a 0.475 M sucrose solution, you will need to weigh out 81.255 grams of sucrose.

Step-by-step explanation:

To calculate the mass of sucrose needed to make a 0.500 L of a 0.475 M solution, use the formula:

mass (g) = molarity (M) × volume (L) × molar mass (g/mol)

Following this:

1. First, multiply the molarity of the solution by the volume of the solution to find the number of moles of sucrose needed:
2. 0.475 M × 0.500 L = 0.2375 mol
3. Next, multiply the number of moles by the molar mass of sucrose to find the mass in grams:
4. 0.2375 mol × 342 g/mol = 81.255 g

Therefore, you will need to weigh out 81.255 grams of sucrose to make a 0.500 L of a 0.475 M sucrose solution.

Answer 2

The first step to solve this problem is to multiply the volume of solution times its concentration to find the number of moles needed, remember that M=mol/L:

`0.500L\cdot(0.475mol)/(L)=0.2375mol`

Now, use the molar mass of sucrose to find the number of grams needed to make the solution. This is, multiply the number of moles needed times the molar mass:

`0.2375mol\cdot(342g)/(mol)=81.225g`

It means that to make 0.500L of a 0.475M you will have to weigh 81.225g of sucrose.