Answer: 1. F = ma
F = 32 kg × 12 m/s2
F = 384 N
2. a=Fm
a
=
F
m
a=20 N4 kg
a
=
20
N
4
kg
a = 5 m/s2
3. Keep in mind that when the car stops, the final velocity is zero. Use the formula for final velocity to calculate the acceleration.
v2 = v1 + at
0 m/s = 30 m/s + (a × 3 s)
0 = 30 + 3a
Subtract 3a from both sides of the equation.
0 − 3a = 30 + 3a − 3a
−3a = 30
Divide both sides of the equation by –3 to solve for a.
a = –10 m/s
The acceleration is negative, which means that the car is slowing down. The force needed to cause such acceleration can be calculated as follows:
F = ma
F = 1,500 kg × (–10 m/s2)
F = –15,000 N
A deceleration or braking force of –15,000 N must be applied to stop the car in 3 seconds.
4. F = mg
F = 20 kg × 9.8 m/s2
F = 196 N
5. F=mg6
F
=
m
g
6
F=7 kg×9.8 m/s26
F
=
7
kg
×
9.8
m/s
2
6
F=68.66
F
=
68.6
6
F = 11.43 N
6. m=Fg
m
=
F
g
m=100 N9.8 m/s2
m
=
100
N
9.8
m/s
2
m = 10.2 kg
Explanation: Pen foster