Sketch the asymptote and graph the function y=8/(x+3)-2

Question

asked Aug 4, 2019 194k views

2 Answers

Punjabi · Answer 1 · 2019-08-10T12:51:31+0000

Answer:

Please find the attached file.

Explanation:

Given:
y=(8)/(x+3)-2

We need to draw the graph of function with asymptote.

For horizontal asymptote:-

$x\rightarrow \infty$

$y=\lim_(x\rightarrow \infty)((8)/(x+3)-2)=-2$

HA: y=-2

For vertical asymptote:-

$y\rightarrow \infty$

x+3=0

VA: x=-3

For x-intercept, Put y=0

(1,0)

For y-intercept, Put x=0

(0,2/3)

Now we will plot on graph and draw the graph.

Please see the attachment for graph.