Question

The circle x^2+y^2=4 has the point _ as its center

Answer 1

HEY THERE!!

Compare the above equation with

`( {x}^(2) - h)( {y}^(2) - k) = {r}^(2) \\ \\ so \: here \: h = and \: k = 0 \\ so \: the \: centre \: is \: (0 \: 0) \: and \: the \: radius \: is \: 2`
Hope it helped you.

Answer 2

Center (0,0)

Radius: 2