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The circle x^2+y^2=4 has the point _ as its center
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1 vote
The circle x^2+y^2=4 has the point _ as its center

User Shawnzhu
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2 Answers

1 vote
HEY THERE!!

Compare the above equation with

( {x}^(2) - h)( {y}^(2) - k) = {r}^(2) \\ \\ so \: here \: h = and \: k = 0 \\ so \: the \: centre \: is \: (0 \: 0) \: and \: the \: radius \: is \: 2
Hope it helped you.
User Prash
by
5.7k points
3 votes

Center (0,0)

Radius: 2

User Tono Nam
by
5.4k points
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