115k views
0 votes
Which is a counterexample for the conditional statement? If a square has side length s, then the perimeter is less than the area. s = 3 s = 5 s = 7 s = 9

User Isidrok
by
8.0k points

2 Answers

5 votes
s=3. the perimeter, 12, is greater than the area, 9
User Mahoni
by
8.2k points
1 vote

Answer:

Side length s = 3 is the counter-example for the given statement.

Explanation:

We are given that the side length of a square = s.

Now, we know that,

Perimeter of a square =
4s

Area of a square =
s^2

Then, the table showing the perimeter and area of a square for different side length is given by,

Side length (s) Perimeter =
4s Area =
s^2

3 12 9

5 20 25

7 28 49

9 36 81

Now, we need a counter-example for the statement,

'If the side length of a square is 's', then the perimeter is less than the area'.

From the table, we see that,

When the side length of the square is 3, then perimeter = 12 > 9 = area.

Thus, side length s = 3 is the counter-example for the given statement.

User Mukesh
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.