Answer:
Side length s = 3 is the counter-example for the given statement.
Explanation:
We are given that the side length of a square = s.
Now, we know that,
Perimeter of a square =

Area of a square =

Then, the table showing the perimeter and area of a square for different side length is given by,
Side length (s) Perimeter =
Area =

3 12 9
5 20 25
7 28 49
9 36 81
Now, we need a counter-example for the statement,
'If the side length of a square is 's', then the perimeter is less than the area'.
From the table, we see that,
When the side length of the square is 3, then perimeter = 12 > 9 = area.
Thus, side length s = 3 is the counter-example for the given statement.