At 95% confidence, how large a sample should be taken to obtain a margin of error of .03 for the estimation of the population proportion? Assume past data are not available for …

Question

asked Sep 17, 2020 76.5k views

2 Answers

Penz · Answer 1 · 2020-09-24T06:02:20+0000

Answer:

The sample should be 1,068.

Explanation:

Consider the provided information.

Confidence level is 95% and margin of error is 0.03.

Thus,

1-α=0.95

α=0.05, E=0.03 and planning value
$\hat p=0.5$

Formula to calculate sample size is:
$n=(\hat p(1-\hat p)(z_(\alpha/2))^2)/(E^2)$

From the table we can find:

$z_(\alpha/2)=z_(0.05/2)\\z_(0.025)=1.96$

Substitute the respective values in the above formula we get:

n=(0.5(0.5)(1.96)^2)/((0.03)^2)

$n=(0.25(1.96)^2)/((0.03)^2)\approx 1067.111$

Hence, the sample should be 1,068.