Register
HELP ME PLSSLSLSPSPS im stuck pls help A 13.3 kg box sliding across the ground decelerates at 2.42 m/s2. What is the coefficient of kinetic friction? (No unit)
33.7k views
0 votes
HELP ME PLSSLSLSPSPS im stuck pls help

A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)

User Mahmoud Mabrok
by
4.5k points

2 Answers

4 votes
The answer is 0.242
User Macbert
by
4.0k points
8 votes
Answer:
0.242
Step-by-step explanation:
m = 13.3 kg
a =d= 2.42 m/s²
g = 10 m/s²
from the laws of friction F = ¶R
===> ¶ = F/R = ma/mg = a/g
¶ = a/g = 2.42/10 = 0.242 hopefully this helped if not i’m sorry:/
User ThoseKind
by
4.4k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.5m questions

5.9m answers

Other Questions

How does the value of the electrostatic force vary with the value (how many) of the charges?
What is the application of physics ​
A car is moving 14.4 m/s when it hits the brakes. It slow from 78.8 m, which take 9.92s. It then accelerates at 1.83 m/s 2 for 4.50 s. What is the total displacement?
A 3.63.kgkg chihuahua charges at a speed of 3.3m/s3.3m/s. What is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s0.50s
5. How does the existence of humans compare with Earth's age?
Link Copied!