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HELP ME PLSSLSLSPSPS im stuck pls help A 13.3 kg box sliding across the ground decelerates at 2.42 m/s2. What is the coefficient of kinetic friction? (No unit)
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HELP ME PLSSLSLSPSPS im stuck pls help

A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)

User Mahmoud Mabrok
by
7.8k points

2 Answers

4 votes
The answer is 0.242
User Macbert
by
7.4k points
8 votes
Answer:
0.242
Step-by-step explanation:
m = 13.3 kg
a =d= 2.42 m/s²
g = 10 m/s²
from the laws of friction F = ¶R
===> ¶ = F/R = ma/mg = a/g
¶ = a/g = 2.42/10 = 0.242 hopefully this helped if not i’m sorry:/
User ThoseKind
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7.0k points
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