Question

HELP ME PLSSLSLSPSPS im stuck pls help

A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)

Answer 1

The answer is 0.242

Answer 2

Answer:
0.242
Step-by-step explanation:
m = 13.3 kg
a =d= 2.42 m/s²
g = 10 m/s²
from the laws of friction F = ¶R
===> ¶ = F/R = ma/mg = a/g
¶ = a/g = 2.42/10 = 0.242 hopefully this helped if not i’m sorry:/