Register
HELP ME PLSSLSLSPSPS im stuck pls help A 13.3 kg box sliding across the ground decelerates at 2.42 m/s2. What is the coefficient of kinetic friction? (No unit)
33.7k views
0 votes
HELP ME PLSSLSLSPSPS im stuck pls help

A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)

User Mahmoud Mabrok
by
4.6k points

2 Answers

4 votes
The answer is 0.242
User Macbert
by
4.0k points
8 votes
Answer:
0.242
Step-by-step explanation:
m = 13.3 kg
a =d= 2.42 m/s²
g = 10 m/s²
from the laws of friction F = ¶R
===> ¶ = F/R = ma/mg = a/g
¶ = a/g = 2.42/10 = 0.242 hopefully this helped if not i’m sorry:/
User ThoseKind
by
4.5k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.6m questions

6.0m answers

Other Questions

How long does it take to cover 5 metre when going at the speed of 1 km/h
What is the difference between mass and density?
How long is a day/night cycle on the moon?
What are three ways in which heat is transferred
On Mars a rock falls an unknown vertical distance from a resting position and lands in a crater. If it takes the rock 2.5 seconds to fall, how high is the cliff the rock fell from? Mars' surface gravity
Link Copied!