Question

In parallelogram defg,, DH = x+3 HF= 3y GH=3x-3 and HE =5y + 4

Answer 1

9 and 4

Explanation:

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Answer 2

The value of x and y is 9 and 4 units

Solution:

We have,

DH = x+3; HF= 3y and GH=3x-3; HE =5y + 4

For parallelogram, we know that,

DH=HF

So,
`(x+3)=3 y\Rightarrow x=(3 y-3)`--------- (i)

Again, GH = HE

So,
`3x-3 = 5y +4`

`\Rightarrow3 x=5 y+4+3`

`x = ((5y+7))/(3)` ………. (ii)

Now equating both (i) and (ii) we get,

`\Rightarrow3 y-3=(5 y+7)/(3)`

`\Rightarrow3*(3y-3) = 5y+7`

`\Rightarrow9y - 9 = 5y +7`

`\Rightarrow9y-5y=7+9`

`\Rightarrow4y = 16`

`\Rightarrow y = 4`

So the value of
`x = 3*4 -3 = 9`

The value of x and y is 9 and 4 units