108k views
3 votes
Colleen divided integer “a” by -6 and got six. Then she divided six by integer B and got -3. Find the quotient of integer a and integer b

Colleen divided integer “a” by -6 and got six. Then she divided six by integer B and-example-1
User AdmSteck
by
8.2k points

2 Answers

3 votes

Answer:

You know that the quotient Colleen got when she divided an integer “a” by -6 was 6.

Explanation:

the other person is correct

User Ali Shekari
by
7.7k points
3 votes

Answer:
(a)/(b)= 18

Explanation:

You know that the quotient Colleen got when she divided an integer “a” by -6 was 6. This can be expressed as:


(a)/(-6)=6

Then, you can find that integer solving for "a":


a=(6)(-6)\\\\a=-36

The quotient Colleen got when she divided 6 by an integer “b” was -3. This can be expressed as:


(6)/(b)=-3

Therefore, you can find that integer solving for "b":


6=(-3)(b)\\\\(6)/(-3)=b\\\\b=-2

Knowing the values of "a" and "b", you can divide these integers in order to find the quotient between thenm


(a)/(b)=(-36)/(-2)}= 18

User Newton Joshua
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories