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Colleen divided integer “a” by -6 and got six. Then she divided six by integer B and got -3. Find the quotient of integer a and integer b

Colleen divided integer “a” by -6 and got six. Then she divided six by integer B and-example-1
User AdmSteck
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2 Answers

3 votes

Answer:

You know that the quotient Colleen got when she divided an integer “a” by -6 was 6.

Explanation:

the other person is correct

User Ali Shekari
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3 votes

Answer:
(a)/(b)= 18

Explanation:

You know that the quotient Colleen got when she divided an integer “a” by -6 was 6. This can be expressed as:


(a)/(-6)=6

Then, you can find that integer solving for "a":


a=(6)(-6)\\\\a=-36

The quotient Colleen got when she divided 6 by an integer “b” was -3. This can be expressed as:


(6)/(b)=-3

Therefore, you can find that integer solving for "b":


6=(-3)(b)\\\\(6)/(-3)=b\\\\b=-2

Knowing the values of "a" and "b", you can divide these integers in order to find the quotient between thenm


(a)/(b)=(-36)/(-2)}= 18

User Newton Joshua
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