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A given line has the equation 10x+2y=-2.

What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0,
12)?
y--5x+12
5x+y=12
y-12=5(x-0)
5x+y=-1

User Abendt
by
6.6k points

2 Answers

4 votes

Answer:

a

Explanation:

its right on edge

4 votes

Answer:

Option 1 -
y=-5x+12

Explanation:

Given : A given line has the equation
10x+2y=-2

To find : What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)?

Solution :

The slope intercept form is
y=mx+c

where, m is the slope and c is the y-intercept.

Writing given equation in slope intercept form,

Equation
10x+2y=-2

Take x to another side,


2y=-10x-2

Divide both side by 2,


y=-5x-1

The slope intercept form of the equation is
y=-5x-1

Where, m=-5 is the slope and c=-1 is the y-intercept.

When two lines are parallel their slopes are equal i.e.
m_1=m_2

Let the equation be
y=mx+c

As lines are parallel then m=-5

We have given lines passes through point (0,12).

Substitute in equation,


12=-5(0)+c


c=12

Substitute back in equation,


y=-5x+12

Therefore, The required equation is
y=-5x+12

So, Option 1 is correct.

User Overdose
by
6.8k points