Answer:
![216\text{ feet}^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bzpn369dj5hrjgrnmrtern7bh1oea17ioy.png)
Explanation:
We have been given that the base of a regular hexagonal pyramid has sides 6 feet long and a slant height of 12 feet. We are asked to find the lateral area of the pyramid.
, where,
p = Perimeter of base of pyramid,
l = Slant height.
Since each side of the the hexagonal base is 6 feet, so perimeter of base would be
feet.
![\text{Lateral area of a regular hexagonal pyramid}=(1)/(2)(36* 12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/crbum140amrxu5fgfco3bxi3674lnbb7v8.png)
![\text{Lateral area of a regular hexagonal pyramid}=18* 12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gp9ia3x521h2sdjor296ddcmeqotrdya63.png)
![\text{Lateral area of a regular hexagonal pyramid}=216](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ccw26s5unffx1fvbj1e1s0f3kcg9nm8ucz.png)
Therefore, the lateral area of hexagonal pyramid would be 216 square feet.