Answer:
-3c
Explanation:
We are given that an expression
![((6c^2+3c)/(-4c+2))/((2c+1)/(4c-2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jjrqsr84wvz9llbyl3ifthl5sn0ma6jvms.png)
We have to find an expression which is equal to given expression
Taking common 3c from nominator and -2 from denominator in dividened and 2 common in divisor then we get
![((3c(2c+1))/(-2(c-2)))/((2c+1)/(2(2c-1)))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/teiv3wcib56is5u3dq905y2s51xhqye1du.png)
![(3c(2c+1))/(-2(2c-1))* (2(2c-1))/((2c+1))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q3wkimp7ipuctlp1o2dj370udm0ofztayi.png)
By reciprocal divisor
By canceling same factor
Then ,we get
![((6c^2+3c)/(-4c+2))/((2c+1)/(4c-2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jjrqsr84wvz9llbyl3ifthl5sn0ma6jvms.png)
=-3c