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Finding angles outside of a circle.

Solve for x :))

Finding angles outside of a circle. Solve for x :))-example-1
User Ilko
by
8.3k points

2 Answers

2 votes

Answer:

x=6

Explanation:

So we have the difference of the intercept arcs divided by 2 is the angle formed by the two tangents there.

So we have


((37x+5)-(23x-5))/(2)=5x+17

Clear the fraction by multiplying both sides by 2:


(37x+5)-(23x-5)=2(5x+17)

Distribute:


37x+5-23x+5=10x+34

Combine like terms on the left hand side:


37x-23x+5+5=10x+34

Simplify:


14x+10=10x+34

Subtract 10x on both sides:


4x+10=34

Subtract 10 on both sides:


4x=24

Divide both sides by 4:


x=6

User Tstseby
by
7.8k points
4 votes

Answer:

23x -5 + 37x + 5= 360

x = 6

Explanation:

User Piddien
by
8.1k points

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