Question

Finding angles outside of a circle.

Solve for x :))

Answer 1

x=6

Explanation:

So we have the difference of the intercept arcs divided by 2 is the angle formed by the two tangents there.

So we have

`((37x+5)-(23x-5))/(2)=5x+17`

Clear the fraction by multiplying both sides by 2:

`(37x+5)-(23x-5)=2(5x+17)`

Distribute:

`37x+5-23x+5=10x+34`

Combine like terms on the left hand side:

`37x-23x+5+5=10x+34`

Simplify:

`14x+10=10x+34`

Subtract 10x on both sides:

`4x+10=34`

Subtract 10 on both sides:

`4x=24`

Divide both sides by 4:

`x=6`

Answer 2

23x -5 + 37x + 5= 360

x = 6

Explanation: