Question

Suppose that you wish to construct a simple ac generator having an output of 12 V maximum when rotated at 60 Hz. A uniform magnetic field of 0.050 T is available. If the area of the rotating coil is 100 cm2, how many turns do you need?

Answer 1

You need 63.66 turns.

Step-by-step explanation:

The number of turns of a magnetic field is given by the following formula:

`N = (V)/(S*T*2\pi f)`

In which N is the number of turns, V is the maximum output voltage, S is the area of the rotating coil, in square meters and T is the measure of the magnetic field and f is the frequency.

In this problem, we have that:

Suppose that you wish to construct a simple ac generator having an output of 12 V maximum when rotated at 60 Hz. This means that
`V = 12` and
`f = 60`.

A uniform magnetic field of 0.050 T is available. This means that
`T = 0.050`.

If the area of the rotating coil is 100 cm2, how many turns do you need?

This means that
`S = 0.01`m². So:

`N = (V)/(S*T*2\pi f)`

`N = (12)/(0.01*0.05*120\pi)`

`N = 63.66`

You need 63.66 turns.

Answer 2

The number of turns is 64.

Step-by-step explanation:

Given that,

Magnetic field = 0.050 T

Area of coil = 100 cm²

Frequency = 60 Hz

Output voltage emf= 12 V

We need to calculate the number of turns

Using formula of induced emf

`emf =NAB\omega`

`N=(emf)/(A* B*2\pi f)`

`N=(12)/(0.01*0.050*2*3.14*60)`

`N =63.6 = 64\ turns`

Hence, The number of turns is 64.