Answer:
The resulting function after the sequence of transformations is
![f(x)=3(x+2)^5+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4hm5f26p54ozfr5wcjdxpzu6oth7dcspnt.png)
Explanation:
Given a function f(x)
- the function a*f(x) will be a vertical stretch of factor a, given a > 1
- the function f(x) + b will be the translated function vertically up b units
- the function f(x+c) will be horizontally translated function of the original by c units left
Remembering these points, we can apply the rules to
.
- Strech vertically by 3 would be
![3x^5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uaon3ym7s15pimi6v0a2b7fssyw9aj2rfs.png)
- translate up 1 unit would be
![3x^(5)+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/90nxiksiuqvajvf4pa2mopcg3f21qamexq.png)
- translate left 2 units would make it
![3(x+2)^5+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xh5yh2r5bqdlz70psml88g7sef4x6c5af5.png)
Hence the new function would be
![3(x+2)^5+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xh5yh2r5bqdlz70psml88g7sef4x6c5af5.png)