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What is the multiplicative rate of change for the exponential function f(x) = 2(5/2)-x

User Eudel
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2 Answers

4 votes

Answer:

0.4

Explanation:

We have been given an exponential function
f(x)=2((5)/(2))^(-x). We are asked to find the multiplicative rate of change.

We will use exponent properties to solve our given problem.

Using property
((a)/(b))^(-1)=((b)/(a))^x, we can rewrite our given function as:


f(x)=2((2)/(5))^(x)


f(x)=2(0.4)^(x)

We know that an exponential function is in form
y=a\cdot b^x, where,

a = Initial value,

b = Multiplicative rate of change.

Upon looking at our given function, we can see that the value of b is 0.4, therefore, the multiplicative rate of change for the given exponential function is 0.4.

User Azpiri
by
7.7k points
0 votes

Answer:

The multiplicative rate of change for the exponential function is 0.4.

Explanation:

Given : Exponential function
f(x) = 2((5)/(2))^(-x)

To find : The multiplicative rate of change for the exponential function.

Solution :

The general form of exponential function is


f(x)=ab^x

where b is the rate of change of the function.

First we write the given function in proper form :


f(x) = 2((5)/(2))^(-x)


f(x) = 2((2)/(5))^(x)

The rate of change is
(2)/(5)=0.4

Therefore, The multiplicative rate of change for the exponential function is 0.4.

User Allan Scofield
by
8.3k points

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