Question

Please Help
Solve for r.

1/3r+1=−2/3r−2

Answer 1

-3

Explanation:

Answer 2

`r=-3`

Explanation:

We have the equation:

`\displaystyle (1)/(3)r+1=-(2)/(3)r-2`

And we would like to solve for r.

First, we can multiply both sides by the denominator 3. This will remove the fractions. So:

`\displaystyle 3((1)/(3)r+1)=3(-(2)/(3)r-2)`

Distribute:

`\displaystyle r+3=-2r-6`

Now, we can add 2r to both sides:

`3r+3=-6`

And we can also subtract 3 from both sides:

`3r=-9`

Finally, we can divide both sides by 3 to get:

`r=-3`