Question

When 5.0 moles of butane react completely?

Answer 1

20.mol of carbon dioxide are produced when 5.0 moles of butane react completely. The correct answer is option 3.

In the given balanced chemical equation

`2C_4H_{10` +
`13O_2` →
`8CO_2` +
`10H_2O`, it is stated that 2 moles of butane (
`C_4H_{10`) react to produce 8 moles of carbon dioxide (
`CO_2` ). This mole ratio is derived from the coefficients of the balanced equation, indicating the proportional relationship between the reactants and products.

If 5.0 moles of butane are reacting, the mole ratio allows us to calculate the moles of carbon dioxide produced using the following conversion:

5.0mol
`C_4H_{10` ×
`(8 mol CO_2)/(2 mol C_4H_(10))` =20.0 mol
`CO_2`

This calculation demonstrates that for every 2 moles of butane reacting, 8 moles of carbon dioxide are produced. Therefore, with 5.0 moles of butane, the expected yield of carbon dioxide is 20.0 moles, supporting the correct answer of (3) 20.0 mol of carbon dioxide.

Answer 2

Moles of Carbondioxide-CO₂ produced = 20 moles

Further explanation

The combustion of hydrocarbons with excess oxygen will produce carbon dioxide and water(CO₂+H₂O), whereas if there is not much oxygen, carbon monoxide and water(CO+H₂O) will be obtained.

The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds

Reaction (combustion of butane) :

2C₄H₁₀+13O₂⇒8CO₂+10H₂O

Butane reacts completely, then Butane is the limiting reactant and oxygen as the excess reactant, so the moles of Carbon dioxide are based on the butane moles as the limiting reactant.

moles of butane - C₄H₁₀ = 5 moles

From the reaction, the mol ratio of C₄H₁₀ and CO₂ : 2 : 8, so mol CO₂ :

`\tt (8)/(2)* 5~moles=20~moles`