Question

HELP In a neutralization reaction, aqueous HCl and aqueous Ba(OH)2 react to form aqueous BaCl2 and water. What volume of 1.50 M HCl will completely neutralize 35.0 mL of 0.520 M Ba(OH)2?

Answer 1

The volume of HCl = 24.27 ml

Further explanation

Reaction

2HCl + Ba(OH)₂ ⇒ BaCl₂ +2 H₂O

mol of Ba(OH)₂ = V x M

`\tt 35* 0.52=18.2mlmol`

From the equation, the mol ratio of HCl : Ba(OH)₂ = 2 : 1, so mol HCl :

`\tt 2* 18.2=36.4~mlmol`

So the volume of HCl :

`\tt n=M* V\\\\V=(n)/(M)\\\\V=(36.4)/(1.5)=24.27~ml`

Or you can use the titration formula :

M₁V₁n₁=M₂V₂n₂(n HCl=1, n Ba(OH)₂=2) :

`\tt 1.5* V_1* 1=0.52* 35* 2\\\\V_1=24.27~ml`