Question

Helpz


`\quad \sf {x}^(2) + 4 = 0`

find value of x ​

Answer 1

Given,

• x² + 4 = 0

Aim :

• To find value of x.

Inorder to calculate the value of x we would transpose the 4 which is in L.H.S. to R.H.S. (Remember that sign would be changed in negative).

>> x² = -4

>> √x² = √-4

>> x = ±2

Therefore,

• Value of x is 2 and -2.

Answer 2

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Answer:
`\textsf{2i and -2i}`

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Given:
`\textsf{x}^2\textsf{ + 4 = 0}`

Find:
`\textsf{The value of x}`

Solution: In order to find the value of x we must isolate x by itself and it will produce the result. In this case we need to subtract 4 from both sides and square root both sides in order to isolate x.

Subtract 4 from both sides

• 
  `\textsf{x}^2\textsf{ + 4 - 4 = 0 - 4}`

• 
  `\textsf{x}^2\textsf{ = 0 - 4}`

• 
  `\textsf{x}^2\textsf{ = - 4}`

Square root both sides

• 
  `\sqrt{\textsf{x}^2}\textsf{ = }\sqrt{\textsf{- 4}}`

• 
  `\textsf{x}\textsf{ = }\sqrt{\textsf{- 4}}`

• 
  `\textsf{x}\textsf{ = }\sqrt{\textsf{ 2}^2\textsf{ * (i)}^2}}`

• 
  `\textsf{x}\textsf{ = }\pm\textsf{2i}`

After completing all of the step we are able to determine that x is equal to both 2i and -2i.