Question

Given the function h(x)=3x+1 and g(x)= x/3 find

a) h^-1 (x)
b)gh^-1 (7)

Answer 1

h‐¹(x)= (x-1)/3

To do this switch the x and y variables in this case it would be x=3y+1 and rearrange to get the y alone

gh‐¹(7)=(x-1)/9=(7-1)/9=2/3

For this section substitutethe x in the g(x) equation with h-¹(x) and then simplify to get your final expression then substitute 7 in place of x to get your integer answer

Hope it's clear, cheers!