Answer:
a) See below
b)
![\huge\boxed{\sf Area\ of\ each\ triangle = 62.4\ in.\²}](https://img.qammunity.org/2021/formulas/mathematics/college/yb4flnmopitfovknt1lsn4en5f3u1q1f7e.png)
c)
![\huge\boxed{\sf Area\ of\ the\ table = 374.4\ in.\²}](https://img.qammunity.org/2021/formulas/mathematics/college/os9eod3i3bysjtho2zf3q054iucwkqdvd3.png)
Explanation:
Part A:
We can draw 3 lines from A to D, B to E and F to C such that all of the lines pass from the center. This will form 6 equal (congruent) triangles.
![\rule[225]{225}{2}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/ri1osubq0ul0fyszs3s2hvchlv85n22xxb.png)
Part B:
Area of each triangle = 1/2 (Base)(Height)
Where Base = 12 in. and Height = 10.4 in.
Area = 1/2 (12) (10.4)
Area = 6 (10.4)
Area of each triangle = 62.4 in.²
![\rule[225]{225}{2}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/ri1osubq0ul0fyszs3s2hvchlv85n22xxb.png)
Part C:
Since the table is mage up of 6 equal triangles:
So,
Area of the table = 6 (Area of each triangle)
Area of the table = 6 (62.4)
Area of the table = 374.4 in.²
![\rule[225]{225}{2}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/ri1osubq0ul0fyszs3s2hvchlv85n22xxb.png)
Hope this helped!
~AH1807