Question

`3a-2b=8\\2a-2b=4`
solve the following simultaneous equations using elimination method

Answer 1

Answer: a = 4, b = 2

Explanation:

=> 3a - 2b = 8 (Eq. 1)
=> 2a - 2b = 4 (Eq. 2)

Subtracting Eq. 2 from 1, we get :-

a = 8 - 4
=> a = 4

Substitute value of ‘a’ in Eq. 1 :-

3a - 2b = 8
3(4) - 2b = 8
12 - 2b = 8
-2b = 8 - 12
-2b = -4
2b = 4
b = 4/2
=> b = 2

Therefore, a = 4 and b = 2

Answer 2

Explanation:

3a−2b=8

Add 2b to both sides.

3a=8+2b

The equation is in standard form.

3a=2b+8

Divide both sides by 3.

3

3a

=

3

2b+8

Dividing by 3 undoes the multiplication by 3.

a=

3

2b+8

3a−2b=8

Subtract 3a from both sides.

−2b=8−3a

Divide both sides by −2.

−2

−2b

=

−2

8−3a

Dividing by −2 undoes the multiplication by −2.

b=

−2

8−3a

Divide 8−3a by −2.

b=

2

3a

−4