Final answer:
The frequency of motion for a 2.0m long pendulum is approximately 0.35 Hz, which can be determined by calculating the period of the pendulum and then finding the reciprocal of the period.
Step-by-step explanation:
The frequency of motion of a 2.0m long pendulum can be calculated using the formula for the period of a simple pendulum:
T = 2π √(l/g)
Where T is the period, l is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.8 m/s² on Earth). To find the frequency (f), which is the reciprocal of the period, we use:
f = 1/T
First, we calculate the period of the pendulum:
T = 2π √(2.0 m / 9.8 m/s²) = 2π √(0.2041s²) ≈ 2π(0.4517s) ≈ 2.837s
Now, we calculate the frequency:
f = 1/2.837s ≈ 0.352 Hz
Therefore, the correct answer is A) 0.35 Hz.