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The equation (m^5/6) (m^1/6) ^7 =m^x what is the value of x that makes the equation true?​

1 Answer

7 votes

Answer:

2

Explanation:

We have the equation


m^(5/6)(m^(1/6))^7=m^x

The exponent rules to be used are


a^x* a^y=a^(x+y)


(a^(x))^y=a^(xy)


m^(5/6)(m)^(7/6)=m^x\\\Rightarrow m^{(5)/(6)+(7)/(6)}=m^x\\\Rightarrow m^{(5+7)/(6)}=m^x\\\Rightarrow m^{(12)/(6)}=m^x\\\Rightarrow m^(2)=m^x

Comparing the exponents we get


x=2

So, the value of
x=2 makes the equation true.

User Andy White
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