Question

The equation (m^5/6) (m^1/6) ^7 =m^x what is the value of x that makes the equation true?​

Answer 1

2

Explanation:

We have the equation

`m^(5/6)(m^(1/6))^7=m^x`

The exponent rules to be used are

`a^x* a^y=a^(x+y)`

`(a^(x))^y=a^(xy)`

`m^(5/6)(m)^(7/6)=m^x\\\Rightarrow m^{(5)/(6)+(7)/(6)}=m^x\\\Rightarrow m^{(5+7)/(6)}=m^x\\\Rightarrow m^{(12)/(6)}=m^x\\\Rightarrow m^(2)=m^x`

Comparing the exponents we get

`x=2`

So, the value of
`x=2` makes the equation true.