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a 3.2 kg durian fruit is pushed across the table.If the acceleration of the durian is 3.1 m/s/s to the right,what is the net force exerted on the fruit?(Fnet=ma)​
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a 3.2 kg durian fruit is pushed across the table.If the acceleration of the durian is 3.1 m/s/s to the right,what is the net force exerted on the fruit?(Fnet=ma)​

User Asare
by
4.2k points

2 Answers

4 votes

Answer:

9.92

Hope I helped

User Yogesh Bhadauirya
by
4.7k points
3 votes

Answer:

9.92 N

Step-by-step explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.2 × 3.1

We have the final answer as

9.92 N

Hope this helps you

User Individualtermite
by
4.6k points
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