Question

What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63

Answer 1

y=x/2−63

Step-by-step explanation: 6x+3y=-63 3y=6x-63= y=2/x-63

Answer 2

The slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2

Explanation:

We know that the slope intercept-form of the line equation is

`y=mx+b`

where m is the slope and b is the y-intercept

Given the equation

`6x+3y=-63`

simplifying the equation to write in the slope-intercept form

`y=-2x-21`

Thus, the slope = -2

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be:

`(-1)/(-2)=(1)/(2)`

Therefore, the slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2