Question

4. The length of a rectangle is eight more than

twice its width. The perimeter is 96 feet. Find
the dimensions of the rectangle.

Answer 1

length = 104/3 ft

width = 40/3 ft

Explanation:

Variables:

L = length

w = width

Set up equations:

• L = 8 + 2w
• 2L + 2w = 96

Substitute L with the first bullet point equation:

2L + 2w = 96

2(8 + 2w) + 2w = 96

16 + 4w + 2w = 96

16 + 6w = 96

6w = 80

w = 40/3 ft

Find L now that you have the value of the width:

L = 8 + 2w

L = 8 + 2(40/3)

L = 8 + 80/3

L = 104/3 ft

Final Values:

length = 104/3 ft

width = 40/3 ft