Question

A circular loop of radius 0.0400 m is

oriented 75.0 degrees to a magnetic
field. If the magnetic flux through the
loop is 9.59 x 10-7 Wb, what is the
strength of the field?

Answer 1

Let's see

Find enclosed area of loop

`\\ \rm\dashrightarrow \pi r^2`

`\\ \rm\dashrightarrow 3.14(0.04)^2`

`\\ \rm\dashrightarrow 0.005m^2`

Now

`\\ \rm\dashrightarrow \phi=BAcos\theta`

• We need B

`\\ \rm\dashrightarrow 9.59* 10^(-7)=B(0.005)cos75`

`\\ \rm\dashrightarrow 9.59* 10^(-7)=0.0046B`

`\\ \rm\dashrightarrow B=2084.78* 10^(-7)`

`\\ \rm\dashrightarrow B=2.08* 10^(-4)T`

`\\ \rm\dashrightarrow B=0.208mT`

Answer 2

Answer:7.37*10^-4

Explanation:B=Ф/A*cos(θ) B=9.59*10^7/(π*0.0400²)*cos(75)=7.37144316*10^-4 =7.37*10^-4