Question

What will happen when a piece of magnesium metal is dropped into a beaker containing a l M solution of copper(1) chloride?

Mg2+ + 2e = Mg(9) P = - 2.37 V
Cu2+ + 2e → Cu(9) ° = + 0.34 V
A. The magnesium will dissolve but nothing else will happen.
B. The magnesium will dissolve and the copper will be deposited
C. The copper will dissolve and the magnesium will be deposited
D. The magnesium will dissolve and chloride gas will be produced E. There will be no reaction,​

Answer 1

When magnesium metal is added to a solution of copper(I) chloride, a metal replacement reaction occurs where magnesium dissolves and copper metal is deposited.

Step-by-step explanation:

When a piece of magnesium metal is dropped into a beaker containing a 1 M solution of copper(I) chloride, a metal replacement reaction occurs. Magnesium is more reactive than copper and will replace the copper in the solution. The balanced chemical reaction is as follows: Mg(s) + 2 CuCl (aq) → MgCl₂ (aq) + 2 Cu(s). The magnesium dissolves, and copper metal is deposited. Therefore, option B is correct: The magnesium will dissolve and the copper will be deposited.