Question

The length of the rectangular poster is 5 more inches than it’s width. The area of the poster is 72 square inches. Solve for the dimensions (length and width) of the poster.

Answer 1

so, the width of the poster is 8.185 inches [rounded] / √67 inches

and the length of the poster is 13.185 inches [rounded] / √67 + 5 inches

Explanation:

( area can be found with the formula l × w [length × width] )

I will call the width "x"

w · l = 72

x · x + 5 = 72

- 5 - 5

x · x = 67

x² = 67

√x² = √67

x ≈ 8.185

(x = √67)

so, by adding 5 inches, we get that

x + 5

8.185 + 5 [√67 + 5]

length = 13.185

so, the width of the poster is 8.185 inches [rounded] / √67 inches

and the length of the poster is 13.185 inches [rounded] / √67 + 5 inches