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Gold has a density of 0.01932 kg/cm³. What volume (in cm³) would be occupied by a 33.3 g

sample of gold?

User Tratcher
by
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1 Answer

6 votes

Answer:

1.72 cm³

Step-by-step explanation:

0.01932 kg/cm³

density is in kilograms

33.3 g into kilograms is 0.0333 kilograms

1.72360248447

0.01932 kg/cm³ means

0.01932 kg/ 1 cm³

I want kg units to cancel out so that I'm left with cm³

0.01932 kg/ 1 cm³ = 1 cm³/.01932 kg

1 cm³/.01932 kg times 0.0333 kg =

0.0333 cm³kg /.01932kg =

kg units cancel out

0.0333 cm³/.01932 which =

1.72360248447 cm³

User Mcvities
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