Question

How do solve this question? Find an equation of a line parallel to the given line and contains the given point. Write the equation in slope–intercept form. With the equation 2x + 5y= -10 point (10, 4).

Answer 1

y = -2/5 x + 8

Explanation:

First we need to find the slope of the given line;

Given the line 2x + 5y= -10, we need to write it in standard form of y = mx+c

Make y the subject of the formula;

2x + 5y= -10

5y = -2x-10

y = -2x/5-10/5

y = -2x/5 - 2

Hence the slope of the line m = -2/5

Since the equation of the line we need is parallel to this line, hence they will have the same slope.

The slope of the required line = -2/5

Get the intercept;

Substitute the point (10,4) and m = -2/5 into the equation y = mx+c

4 = -2/5(10)+c

4 = -4 + c

c = 8

Get the required equation;

y = mx+c

y = -2/5 x + 8

Hence the equation of a line parallel to the given line and contains the given point is y = -2/5 x + 8