Explanation:
I'm going to explain this in standard slope intercept form (y=mx+b) because it is easiest for this situation. I will also include converting it to point slope form. I will also show how to do straight into point slope form if you find that more helpful.
First thing is to identify difference in x and y in both points. From point 1 to point to, the x changes -4 and the y changes +4. We can rapresent this in rise over run fraction
![(4)/( - 4) = - 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/z08joworuaps2zjr71a987kpl8nbg7ucp0.png)
So the slope is -1 because the slope is the simplified rise over run fraction.
Our next step is to find the y-intercept. This is easy because the first point is the y-intercept, so -3 is our y-intercept.
Now we know the equation.
![y = - x - 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/sjb9m9r6bwb6aply5wfjijmf1iyecspyey.png)
All we have to do now is convert it into point-slope form. So here is point slope form: y + y1 = m(x + x1). Y1 is the y-intercept and m is the slope.
![y - 3 = - 1(x + x1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/82mxey3chb2cwh3vo2q602f9nxe5qycexq.png)
So x1 is the x intercept, so to find this you find the x value when y is 0. You can do this by using the standard form I've done because it is easiest.
![0 = - x - 3 \\ x = - 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/8f2vwpylwzoli68xptfcp8git5t7lqwtc9.png)
So when y is 0, then x is -3. Here is the complete point slope form of the line.
![y - 3 = - 1(x - 3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/orwapptavmjxbibsrgruue9y7utxpvbu4g.png)
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To put the line directly into point slope for you need to find the slope, y-intercept, and x-intercept and place the values in accordingly. If you aren't given the y-intercept and x-intercept straight away it can be difficult for some putting it directly in point slope form. That is why I recommend putting it into standard form then point-slope form.