Question

Plz help me asnwer this

Answer 1

x= 0

y= -3

Explanation:

6x-5y=15

substitution...

6(y+3)-5y=15

6y+18-5y=15

y+18=15

-18 -18

y= -3

substitution again...

6x-5(-3)=15

6x+15=15

-15 -15

6x=0

/6 /6

x= 0

Answer 2

(0, -3)

x = 0

y = -3

General Formulas and Concepts:

Pre-Algebra

• Order of Operations: BPEMDAS
• Equality Properties

Algebra I

• Solving systems of equations using substitution/elimination

Explanation:

Step 1: Define systems

6x - 5y = 15

x = y + 3

Step 2: Solve for y

Substitution

1. Substitute in x: 6(y + 3) - 5y = 15
2. Distribute 6: 6y + 18 - 5y = 15
3. Combine like terms: y + 18 = 15
4. Isolate y: y = -3

Step 3: Solve for x

1. Define original equation: x = y + 3
2. Substitute in y: x = -3 + 3
3. Add: x = 0