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Solve for theta to the nearest degree​

Solve for theta to the nearest degree​-example-1
User Plannapus
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Explanation:

So first thing is to determine which trigonometric ratio we use here. Theta is adjacent to 5 and 8 is the hypotenuse, so we should be using Cosine.

So we set up the equation

cos θ = adj/hype

cos θ = 5/8

θ =
cos^(-1) (5/8)

θ=51.3178125...

θ=51°

User Ragu Natarajan
by
7.9k points

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