Question

Solve 5x^2=180 algebraically

Answer 1

Hi...

Given:

`\texttt{5x}`²
`\texttt{= 180}`

Solution:

`\texttt{5x}`²
`\texttt{= 180}`

Step-by-step explanation:

Divide both sides by 5

`\hookrightarrow{\mathtt{(5x^2)/(5)} = {\mathtt{(180)/(5)}`

Simplify:

`\hookrightarrow{\mathtt{x^2 = 36}`

`\hookrightarrow{\mathtt{For \: x^2 \: = f(a) \: the \: solutions \: are \: x = √(f(a))}` ,
`\mathtt{- √(f(a))}`

`\hookrightarrow{\mathtt{x = √(36)}` ,
`\mathtt{x = -√(36)}`

Factor the number: 36 = 6²

`\mathtt{= √(6^2)}`

Apply radical rule:
`\mathtt{\sqrt[n]{a^n} \: = a}`

`\mathtt{√(6^2) = 6} \\\mathtt{= 6}`

-
`√(36) = -6`

`\boxed{\fbox{\bf{x = 6 , x = -6}}}`

Hope It Helps You...

Answer 2

x = ± 6

Step-by-step explanation:

Hello!

Solve

• 
  `5x^2 = 180`
• 
  `x^2 = 180/5`
• 
  `x^2 = 36`
• 
  `√(x^2) = √(36)`
• 
  `x = \pm 6`

The value of x is 6 or -6.